How to start carrier as a java developer



If you want to be a java professional and want to start your carrier in the field of programming so this post is for you read this till the end you will definitely get something which will enhance your confidence as a developer.

There are so many websites available and so many courses available where you can learn programming but if you want to get preference from others you should have something which you can show in your resume so here is some course provided by oracle. Oracle is not just providing certification in java but there are other courses like DBMS and many more you can choose according to your interest.

Oracle provides certification in 5 levels they are as follows:

1.       The Oracle Certified Associate (OCA)

2.       The Oracle Certified Professional (OCP)

3.       The Oracle Certified Master (OCM)

4.       The Oracle Certified Expert (OCE)

5.       The Oracle Certified Specialist (OCS)

 You can choose any level according to your knowledge level 

This is a programmer level certification anyone want to start career as a developer can join this:

Java SE 6 Programmer Certified Professional exam code (1Z0-851)

 

And this exam is not going to be easy you have to prepare really very well passing score is 61% .

To prepare for this you can choose online as well as offline medium there are so many websites and offline institute provide preparations for this.

This is the course provided by oracle to know more about this course visit

www.oracle.com
Or you can also directly enter the exam code provided above in your browser for more information.

Here is the link where you can prepare online for this course

www.durgasoft.com
There are thousands of tests available online you can prepare from that also.
Sample question for scjp-6:

Given classes defined in two different files:
   1. package util;
   2. public class BitUtils {
   3. public static void process(byte[]) { /* more code here */ }
   4. }
   1. package app;
   2. public class SomeApp {
   3. public static void main(String[] args) {
   4. byte[] bytes = new byte[256];
   5. // insert code here
   6. }
   7. }
What is required at line 5 in class SomeApp to use the process method of BitUtils?
1)
SomeApp cannot use methods in BitUtils.
2)
util.BitUtils.process(bytes);
3)
BitUtils.process(bytes);
4)
process(bytes);
5)
import util.BitUtils.*; process(bytes);

Your Selected options   ::   3
Correct Options             ::   2

  

Click Here for Explanation
Answer
::   
option 2



explanation
::  
--

2)   
class Test
{
  public static void main(String[] args)
  {
            String s1="durga";
            String s2="durga";
            String s3=s2;
            System.out.println(s1.equals(s2));
            System.out.println(s2.equals(s3));
            StringBuffer sb1=new StringBuffer("durga"); 
            StringBuffer sb2=new StringBuffer("durga"); 
            StringBuffer sb3=new StringBuffer(sb2); 
            StringBuffer sb4=sb3;
            System.out.println(sb1.equals(sb2));
            System.out.println(sb2.equals(sb3));
            System.out.println(sb3.equals(sb4));
  }
}
1)
true,true,false,false,true
2)
false,false,true,false,true
3)
true,true,true,true,true
4)
true,true,true,false,true
5)
compile time error

Your Selected options   ::   none
Correct Options             ::   1

  

Click Here for Explanation
Answer
::   
option 1



explanation
::  
String class overriding "equlas()" method and if the value of both object is same then it returns true otherwise false.But StringBuffer class doesn't override "equals()" method. So calling equals() method on StringBuffer object always execute from "Object" class which compares the reference,if both object references are same then "Object" class equals() method returns true otherwise false.
3)   
Given:
   11. public static void main(String[] args) {
   12. String str = "null";
   13. if (str == null) {
   14. System.out.println("null");
   15. } else (str.length() == 0) {
   16. System.out.println("zero");
   17. } else {
   18. System.out.println("some");
   19. }
   20. }
What is the result?
1)
Compilation fails.
2)
some
3)
zero
4)
null
5)
An exception is thrown at runtime.

Your Selected options   ::   none
Correct Options             ::   1

  




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